Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q241. |
|
| 1) | 2:3 | 2) | 4:5 |
| 3) | 3:4 | 4) | 6:7 |
| 5) | None of these | ||
Answer : 2:3
Explanation : Given,

Explanation : Given,

View AnswerQ242. |
|
| 1) | Rs.17,000 | 2) | Rs.20,000 |
| 3) | Rs.25,500 | 4) | Rs.38,000 |
| 5) | None of these | ||
Answer : Rs.38,000
Explanation :

Explanation :

View AnswerQ243. |
|
| 1) | 20 litres | 2) | 30 litres |
| 3) | 40 litres | 4) | 60 litres |
| 5) | None of these | ||
Answer : 60 litres
Explanation :

Explanation :

View AnswerQ244. |
|
| 1) | 2 : 5 | 2) | 3 : 5 |
| 3) | 4 : 5 | 4) | 6 : 7 |
| 5) | None of these | ||
Answer : 4 : 5
Explanation :

Explanation :

View AnswerQ245. |
|
| 1) | 24 | 2) | 38 |
| 3) | 42 | 4) | 48 |
| 5) | Non of these | ||
Answer : 38
Explanation :
Explanation :
Let, the numbers be x and x + 2.
Then, (x + 2)2 - x2 = 84
or 4x + 4 = 84 or 4x = 80
or x = 20. The required sum = x + (x + 2) = 2x + 2 = 42.
View AnswerQ246. |
|
| 1) | 235 | 2) | 253 |
| 3) | 273 | 4) | 352 |
| 5) | None of these | ||
Answer : 253
Explanation :
Explanation :
Let, the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred's digits is smaller than the unit's digit.
Hence, required number = 253.
View AnswerQ247. |
|
| 1) | 18 | 2) | 24 |
| 3) | 42 | 4) | 81 |
| 5) | None of these | ||
Answer : 24
Explanation :
Explanation :
Let, the ten's and unit digit be x and y respectively.
So, xy = 8 and the number be 10x+y
When 18 is added, the number be 10x+ y +18.
Then, 10x + y + 18 = 10 y + x
or 9x - 9y = -18 x - y = - 2
We know that (x+y)2=( x-y)2 + 4xy = (-2)2 + 4 x 8 =36
or x+y = 6
By solving we get x = 2 and y = 4
Thus, the number is 24.
View AnswerQ248. |
|
| 1) | 3 | 2) | 5 |
| 3) | 10 | 4) | 11 |
| 5) | None of these | ||
Answer : 11
Explanation :
Explanation :
Let, the ten's digit be x and unit's digit be y.
Then, number = 10x + y.
Number obtained by interchanging the digits = 10y + x.
(10x + y) + (10y + x) = 11(x + y), which is divisible by 11
View AnswerQ249. |
|
| 1) | 4 | 2) | 8 |
| 3) | 12 | 4) | 14 |
| 5) | None of these | ||
Answer : 8
Explanation :
Explanation :
Since the number is greater than the number obtained on reversing the digits, so the ten's digit is greater than the unit's digit.
Let, ten's and unit's digits be 2x and x respectively.
Then, (10 x 2x + x) - (10x + 2x) = 36
or 9x = 36
or x = 4.
So, required difference = (2x + x) - (2x - x) = 2x = 8.
View AnswerQ250. |
|
| 1) | 1 | 2) | 53 |
| 3) | 66 | 4) | 67 |
| 5) | None of these | ||
Answer : 66
Explanation :
Explanation :
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
View Answer
