Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q21. |
|
| 1) | 2:3 | 2) | 3:2 |
| 3) | 1:3 | 4) | D.I |
| 5) | None of these | ||
Answer : 2:3
Explanation :
Explanation :
Let, the first number be x and second number be y.

View AnswerQ22. |
|
| 1) | Rs. 4 | 2) | Rs. 5 |
| 3) | Rs. 6.25 | 4) | Rs. 6.50 |
| 5) | None of these | ||
Answer : Rs. 5
Explanation :
Explanation :

View AnswerQ23. |
|
| 1) | 35 | 2) | 45 |
| 3) | 40 | 4) | 30 |
| 5) | None of these | ||
Answer : 40
Explanation :
Explanation :
Passing marks = 112 - 32 = 80
Also, 75% of total marks = 80 + 70 = 150
Total mark = 200
Then, reqd % = (80/200) x 100 = 40%
View AnswerQ24. |
|
| 1) | 36 | 2) | 40 |
| 3) | 44 | 4) | 48 |
| 5) | None of these | ||
Answer : 48
Explanation :
Explanation :
Let the previous wages be ‘X’
X + (25/100) x =60
or 5x/4 = 60
or x = 48
View AnswerQ25. |
|
| 1) | 304 | 2) | 308 |
| 3) | 312 | 4) | 316 |
| 5) | None of these | ||
Answer : 308
Explanation :
Explanation :
Let the no. be x.
68% of x = 48% of x = 880
(20/100) x = 880
x = 88000 /20= 4400
7% of 4400 = 4400 x (7/100) = 308
View AnswerQ26. |
|
| 1) | 6250 | 2) | 6325 |
| 3) | 5750 | 4) | 5250 |
| 5) | None of these | ||
Answer : 6325
View AnswerQ27. |
|
| 1) | 10% | 2) | 30% |
| 3) | 15% | 4) | 85% |
| 5) | None of these | ||
Answer : None of these
View AnswerQ28. |
|
| 1) | 606 | 2) | 610 |
| 3) | 580 | 4) | 600 |
| 5) | None of these | ||
Answer : 600
View AnswerQ29. |
|
| 1) | 18 | 2) | 20 |
| 3) | 24 | 4) | 28 |
| 5) | None of these | ||
Answer : 24
Explanation :
Explanation :
(vegiterian 60% + 30% had non-vegetarian) - 15% had both = 75% eat either type of lunch
People who do no have either lunch were = 100% - 75% = 25%
So, People who do no have either lunch were = (96 x 25)/100 = 24
View AnswerQ30. |
|
| 1) | 65 | 2) | 80 |
| 3) | 100 | 4) | 120 |
| 5) | None of these | ||
Answer : 100
Explanation :
Explanation :
Students who play cricket, n(A) = 325
Students who play football, n(B) = 175
Total students who play either or both games, = n(A∪B) = 450 − 50 = 400
Required Number,n(A∩B) = n(A)+n(B)−n(A∪B) = 325+175−400 = 100
View Answer
