Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q21. |
|
| 1) | 96 sq.ft. | 2) | 100 sq.ft. |
| 3) | 126 sq.ft. | 4) | 144 sq.ft. |
| 5) | None of these | ||
Answer : 126 sq.ft.
Explanation :
Explanation :
Given, l = 9 ft.
Then, l + 2b = 37
=> 2b = 37 - l = 37 - 9 = 28
=> b = 28/2 = 14 ft.
So, area = lb = 9 × 14 = 126 sq. ft.
View AnswerQ22. |
|
| 1) | 72 feet | 2) | 84 feet |
| 3) | 88 feet | 4) | 96 feet |
| 5) | None of these | ||
Answer : 88 feet
Explanation :
Explanation :
Given, the area of the field = 680 sq. feet
⇒ lb = 680 sq. feet
Length = l = 20 feet
⇒ 20 × b = 680
⇒ b=680/20 = 34 feet
So, required length of the fencing = l + 2b = 20 + (2 × 34) = 88 feet
View AnswerQ23. |
|
| 1) | 90 m | 2) | 80 m |
| 3) | 90 m | 4) | 120 m |
| 5) | None of these | ||
Answer : 120 m
View AnswerQ24. |
|
| 1) | 8 cm | 2) | 9 cm |
| 3) | 12.5 cm | 4) | 18 cm |
| 5) | None of these | ||
Answer : 18 cm
Explanation :
Explanation :
A1= [(1/2) x 15 x 12]cm2 = 90 cm2 . A2 = 2A1 = 180 cm2.
= (1/2) x 20 x h = 180 or h = 18 cm.
View AnswerQ25. |
|
| 1) | 1600 cm2 | 2) | 2400 cm2 |
| 3) | 3600 cm2 | 4) | 4800cm2 |
| 5) | None of these | ||
Answer : 2400 cm2
Explanation :
Explanation :
AB = 26 cm and AC = (1/2) x 48 cm ; OA = 24 cm
OB2 = AB2 - OA2 = (26)2 - (24)2 = (26 + 24) (26 - 24) = 100
or OB = 50 cm or BD = 2 x OB = (250) cm = 100 cm.
Therefore , Area = 1/2 x (AC x BD ) = [(1/2 ) x 48 x100 ] cm2 = 2400 cm2.
View AnswerQ26. |
|
| 1) | 80% | 2) | 88% |
| 3) | 110% | 4) | Can't be determined |
| 5) | None of these | ||
Answer : 88%
Explanation :
Explanation :
According to AB Methods:
New area = -20+10 - (20x10)/100 = -12%
So, required percentage
= (100 - 12 ) = 88%.
View AnswerQ27. |
|
| 1) | 48 | 2) | 56 |
| 3) | 76 | 4) | 88 |
| 5) | None of these | ||
Answer : 88
Explanation :
Explanation :
We have, L = 20 ft and LB = 680 sq.ft
So, b = 680/20 = 34 ft.
Length of fencing (L+2B) = (20 + 68) ft = 88 ft.
View AnswerQ28. |
|
| 1) | 4cm, 20 | 2) | 6cm, 10 |
| 3) | 2cm, 20 | 4) | 4cm, 30 |
| 5) | None of these | ||
Answer : 4cm, 30
Explanation :
Explanation :
Size of the largest possible square tile
= H.C.F ( 24, 20) = 4 m.
So,number of tiles required [(24 x 20)/(4x4) ]=30
View Answer
