Mathmetics
ISBT Mathmetics for all banking PO,Clerk,IBPS PO,Railway,SSC,IAS,OAS Exams
Q521. |
Direction : Answer the questions based on the given line graph. Ratio of Exports to Imports (in terms of money in Rs. crores) of Two Companies Over the Years ![]() In which year(s) was the difference between impors and exports of Company B the maximum ? |
| 1) | 1995 | 2) | 1996 |
| 3) | 2000 | 4) | Cannot be determined |
| 5) | None of these | ||
Answer : Cannot be determined
View AnswerQ522. |
Direction : Answer the questions based on the given line graph. Ratio of Exports to Imports (in terms of money in Rs. crores) of Two Companies Over the Years ![]() In 1995, the export of Company A was double that of Company B. If the imports of Company A during the year was Rs. 180 crores, what was the approximate amount of imports pf Company B during that year? |
| 1) | Rs. 180 crores | 2) | Rs. 200 crores |
| 3) | Rs. 210 crores | 4) | Cannot be determined |
| 5) | None of these | ||
Answer : Rs. 210 crores
View AnswerQ523. |
Direction : Answer the questions based on the given line graph. Ratio of Exports to Imports (in terms of money in Rs. crores) of Two Companies Over the Years ![]() If the exports of Company A in 1998 were Rs. 237 crores, what was the amount of imports in that year ? |
| 1) | Rs. 216 crores | 2) | Rs. 240 crores |
| 3) | Rs. 284 crores | 4) | Rs. 316 crores |
| 5) | None of these | ||
Answer : Rs. 316 crores
Explanation :
Explanation :
Let, the amount of imports of Company A in 1998 be Rs. x crores.
Then,237/x= 0.75
=> x = 237/0.75 = 316.
Therefore, amount of imports of Company A in 1998 = Rs. 316 crores.
View AnswerQ524. |
Direction : Answer the questions based on the given line graph. Ratio of Exports to Imports (in terms of money in Rs. crores) of Two Companies Over the Years ![]() If the imports of Company A in 1997 were increased by 40 %, what would be the ratio of exports to the increased imports ? |
| 1) | 1.10 | 2) | 1.20 |
| 3) | 1.25 | 4) | Cannot be determined |
| 5) | None of these | ||
Answer : 1.25
Explanation :
Explanation :
In 1997 for Company A we have:
E /I = 1.75 i.e., E = 1.75I
where E amount of exports, I = amount of imports of Company A in 1997.
Now, the required imports I1 = I + 40% of I = 1.4I.
Therefore, required ratio =E/I1 =1.75I/1.4I= 1.25.
View AnswerQ525. |
Direction : Answer the questions based on the given line graph. Ratio of Exports to Imports (in terms of money in Rs. crores) of Two Companies Over the Years ![]() In how many of the given years were the exports more than the imports for Company A ? |
| 1) | 2 | 2) | 3 |
| 3) | 4 | 4) | 5 |
| 5) | None of these | ||
Answer : 3
Explanation :
Explanation :
The exports are more than imports in those years for which the exports to imports ratio are more than 1. For Company A, such years are 1995, 1996 and 1997.
Thus, during these 3 years, the exports are more than the imports for Company A.
View AnswerQ526. | Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
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| 1) | 0.1% | 2) | 0.5% |
| 3) | 1% | 4) | 1.25% |
| 5) | None of these | ||
Answer : 1%
View AnswerQ527. | Expenditures of a Company (in Lakh Rupees) per Annum Over the given Years.
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| 1) | Rs. 32.43 lakhs | 2) | Rs. 33.72 lakhs |
| 3) | Rs. 34.18 lakhs | 4) | Rs. 36.66 lakhs |
| 5) | Non Of These | ||
Answer : Rs. 36.66 lakhs
Explanation :
Explanation :
Average amount of interest paid by the Company during the given period
| = Rs. | ![]() | 23.4 + 32.5 + 41.6 + 36.4 + 49.4 | ![]() | lakhs |
| 5 |
| = Rs. |
View AnswerQ528. |
|
| 1) | 1/2 | 2) | 1/3 |
| 3) | 4/9 | 4) | 8/21 |
Answer : 1/3
Explanation :
Explanation :
Total number of balls = n(S) = (8 + 7 + 6) = 21.
Let E = event that the ball drawn is neither red nor green = event that the ball drawn is blue.
So, n(E) = 7.
Therefore, P(E) = n(E) / n(S) = 7 / 21=1 /3 .
View AnswerQ529. |
|
| 1) | 1/6 | 2) | 1/9 |
| 3) | 1/8 | 4) | 1/12 |
| 5) | None of these | ||
Answer : 1/9
Explanation :
Explanation :
In two throws of a die, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)} = 4.
P(E) = n(E)/n(S) = 4/36 = 1/9 .
View AnswerQ530. |
|
| 1) | 1/5 | 2) | 2/5 |
| 3) | 2/7 | 4) | 3/5 |
| 5) | None of these | ||
Answer : 2/7
Explanation :
Explanation :
Thus, P (getting a prize) =10 /(10 + 25) =10 /35 = 2 / 7
View Answer



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